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7v^2-56v=0
a = 7; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·7·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*7}=\frac{0}{14} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*7}=\frac{112}{14} =8 $
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